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lara31 [8.8K]
3 years ago
6

The cost of 9 donuts is $5.50. how many donuts can you buy for $33.00

Mathematics
1 answer:
mash [69]3 years ago
4 0

9514 1404 393

Answer:

  54

Step-by-step explanation:

Let d represent the number of donuts. The cost is proportional to the number, so we have ...

  d/33.00 = 9/5.50

  d = 33.00(9/5.5) = 9·6 = 54

You can buy 54 donuts for $33.00.

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Write the following numbers in order of size start with the smallest. 0.32 0.4 0.35 0.309
fenix001 [56]

Answer:

Hey!

0.309<0.32<0.35<0.4

hope this helps you

6 0
3 years ago
The perimeter of a rectangular playground is 46m. If the length of the park is 7m, what is the width of the park?
HACTEHA [7]

Answer:

16m

Step-by-step explanation:

Since the length of the park is 7m, then the other side is also 7m so 46-14 is 32. So 32/2 is 16.

4 0
3 years ago
From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21
ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:  

We are going to take 4 of the 5 even numbers in the box so we have

5C4=5

Case 2: When all 4 numbers are odd:  

We are going to take 4 of the 5 odd numbers in the box, so we have

5C4=5

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

 

5C2 * 5C2

Remember that we obtain the probability from

\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:  

We are taking 4 of the 10 cards:

10C_4=210

Hence we have that the probability that their sum is even

\frac{5+5+100}{210}=\frac{11}{21}

8 0
3 years ago
A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
nalin [4]

Answer:

Option 2 - Approximately 24–36 pounds

Step-by-step explanation:

Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.

To find : What range of weights would 99.7% of the dogs have?

Solution :

The range of 99.7% will lie between the mean ± 3 standard deviations.

We have given,

Mean weight of Eskimo dogs is \mu=30

Standard deviation of Eskimo dogs is \sigma=2

The range of weights would 99.7% of the dogs have,

R=\mu\pm3\sigma

R=30\pm3(2)

R=30\pm6

R=30+6,30-6

R=36,24

Therefore, The range is approximately, 24 - 36 pounds.

So, Option 2 is correct.

5 0
3 years ago
Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x), and express P in the form P(x)
WINSTONCH [101]
Attached is the solution, long division is hard to type out.
Hope it helps.

6 0
3 years ago
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