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3 years ago

Plzzzzz help me plzzz

Physics

2 answers:

yarga [219]3 years ago

6 0

8 miles per hour

(extra space)

MrRissso [65]3 years ago

4 0

The bike will go eight miles an hour. Hope this answers your question! Have a nice day! :)

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garri49 [273]

Answer:

Explanation:

When a player throws a football , he applies force on the ball , due to which ball accelerates in forward direction . This is the action force .

The ball also applies a force on the hand of the player . Due to it the player experiences a pushing force in backward direction . This is reaction force .

Due to this force , the player does not move in backward direction because of frictional force of the ground . The frictional force keeps him stationary .

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Which property of X-rays allows them to enter our bodies and create pictures of our bones and other internal structures?

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Answer:

(A) Their high energy

Explanation:

The higher the energy of the x-ray the more "likely" they will pass through.

The x-ray is electromagnetic energy caused by energy changes in an electron.

X-ray are energetic and have enough energy to break up molecules. That is what reveals the bad or damaged cells in our body.

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3 years ago

a physical science textbook has a mass of 2.2 kg. If the textbook weighs 19.6 newtons on Venus, what is the strength of gravity

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3 years ago

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A player kicks a football from ground level with a velocity of 26.2m/s at an angle of 34.2° above the horizontal. How far back f

Amanda [17]

For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.

For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.

<h3>Explanation</h3>

How long does it take for the ball to reach the goal?

Let the distance between the kicker and the goal be $x$ meters.

Horizontal velocity of the ball will always be $26.2\times\cos{34.2\textdegree}$ until it lands if there's no air resistance.

The ball will arrive at the goal in $\displaystyle \frac{x}{26.2\times\cos{34.2\textdegree}}$ seconds after it leaves the kicker.

What will be the height of the ball when it reaches the goal?

Consider the equation

$\displaystyle h(t) = -\frac{1}{2}\cdot g\cdot t^{2} + v_{0,\;\text{vertical}} \cdot t + h_0$ .

For this soccer ball:

$g = 9.81\;\text{m}\cdot\text{s}^{-2}$ ,
$v_{0,\;\text{vertical}} = 26.2\times \sin{34.2\textdegree{}}\;\text{m}\cdot\text{s}^{-2}$ ,
$h_0 = 0$ since the player kicks the ball "from ground level."

$\displaystyle t=\frac{x}{26.2\times\cos{34.2\textdegree}}$

when the ball reaches the goal.

$\displaystyle h= - 9.81 \times \frac{x^2}{(26.2\times\cos{34.2\textdegree})^2} + (26.2 \times \sin{34.2\textdegree})\times\frac{x}{26.2\times\cos{34.2\textdegree}} \\\phantom{h} = -\frac{9.81}{(26.2\times\cos{34.2\textdegree})^2}\cdot x^{2} + \frac{\sin{34.2\textdegree}}{\cos{34.2\textdegree}}\cdot x$ .

Solve this quadratic equation for $x$ , $x > 0$ .

$x = 65.1$ meters when $h = 0$ meters.
$x = 6.54$ or $58.5$ meters when $h = 4$ meters.

In other words,

For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.
For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.

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3 years ago

The main component of all computer memory is

never [62]

Hi!

The main component of all computer memory is RAM.

Hope this helps !

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3 years ago

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