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hjlf
3 years ago
13

A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note?

Physics
1 answer:
pickupchik [31]3 years ago
4 0
The equation for wave speed is:

v=\lambda * f

where "v" is wave speed, "λ" is wavelength and "f" is frequency.

Given the wave speed is 343m/s and the wavelength is 0.77955m, we can rewrite the equation as:

\frac{v}{\lambda}  = f

Substituting known values, we get:

\frac{343}{0.77955} =f

f=439.9974344

The pitch that's the closest to this value is Pitch A.
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Answer:

\boxed{F_{net} = 28.7 \ N}

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