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Oduvanchick [21]
3 years ago
7

An 8.0-newton wooden block slides across a

Physics
1 answer:
yanalaym [24]3 years ago
7 0
If the block is sliding at constant velocity then its speed is constant. That means it is not losing any kinetic energy. There is no friction acting and the coefficient of kinetic friction is zero. Sadly, that choice of answer is not offered.
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Find the value of 02?
TiliK225 [7]
My educated guess : 21.2 deg
3 0
3 years ago
An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
2 years ago
A box falls out of a stationary helicopter hovering 135 m above the ground. How long will it take to hit the ground?
Marrrta [24]

We have the equation of motion s = ut + \frac{1}{2} at^2, where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 135 m, Initial velocity = 0 m/s, acceleration = 9.81 m/s^2

Substituting

   135 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 =135\\ \\ t =5.25 seconds

A box falls out of a stationary helicopter hovering 135 m above the ground will take 5.25 seconds to reach the ground.

4 0
3 years ago
If the mass of an object is 10 Kg and it experiences a Net force of 60 Newtons. What is the acceleration?
Solnce55 [7]

Answer:

6 m/s^2

Explanation:

F = ma

60N = (10 kg)a

a = 6m/s^2

3 0
2 years ago
True or false: Relative to the shoreline, a boat always moves in the direction in which it is pointing.
Alja [10]

Answer:

False

Explanation:

A boat can go reverse like a car

3 0
2 years ago
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