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lys-0071 [83]
3 years ago
15

How much work can be extracted from 5.00 × 10^4 J of heat when 2.00 × 10^4 J of heat is exhausted? A. - 7.00 × 10^4 J B. - 3.00

× 10^4 J C. 3.00 × 10^4 J D. 7.00 × 10^4 J ***thank you:)
Physics
1 answer:
docker41 [41]3 years ago
5 0
C.
Work=Q(extracted)-Q(exhausted)=3×10^4 J
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Answer:

The net force acting on the object is doubled while the mass of the object is held constant. What will be the new acceleration? An object has an acceleration of 12.0 m/s^2. The net force acting on the object is halved (decreased to one half its original value) while the mass of the object is held constant.

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viewed from earth two stars form an angle of 76.04 degrees. StarA is 23.30 light years from earth star Bis 34.76 light years fro
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The observation point on Earth and the two stars form a triangle. The two sides of the triangle are 23.3 ly and 34.76 ly and their included angle is 76.04°. We can use the cos rule to find the third side, which is the distance between the two stars.
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3 years ago
An air craft heads north at 320 km/hr relative to the wind. the wind velocity is 80km/hr from the north. find the relative veloc
Gnoma [55]

Answer:

Relative to the ground, the velocity of the aircraft is 240 km/hr

Explanation:

Relative velocity is different from normal velocity;

When 2 objects are moving in opposite directions towards each other, they will appear to be faster than they actually are;

This is known as the relative velocity;

The information tells us we have the aircraft moving 320 km/hr northwards relative to the wind;

The wind is in the opposite direction at 80 km/hr;

R = relative velocity of the aircraft

v = actual velocity of the aircraft

w = velocity of the wind

R = v + w

Note: if the wind was moving in the same direction, the formula would be R = v - w

320 = v + 80

v = 320 - 80

v = 240

The velocity relative to the ground is simply the actual velocity as the ground doesn't move;

So, relative to the ground, the velocity of the aircraft is simply 240 km/hr

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Acceleration(a) is the change in velocity(Δv) over the change in time(Δt). so just divide your velocity and time.
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balu736 [363]

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Explanation: I try to do your question, hope this help

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2 years ago
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