Moles of Carbon dioxide : 13.5
<h3>Further explanation</h3>
Given
4.5 moles propane
Required
moles of Carbon dioxide
Solution
Reaction(Combustion of Propane) :
<em>C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g)</em>
In a chemical equation, the reaction coefficient shows the mole ratio of the reacting compounds (either in reactants or products)
From the equation, mol ratio of Propane(C₃H₈) : Carbon dioxide(CO₂) : 1 : 3, so mol CO₂ :
= 3/1 x mol Propane
= 3 x 4.5 moles
= 13.5 moles
Answer:
A volume of 236 L and a temperature of 10.0 ° C has a pressure of 25.3 kPa.
Explanation:
Boyle's law says that "The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure." Boyle's law is expressed mathematically as: P * V = k
Gay-Lussac's law can be expressed mathematically as follows:
This law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Finally, Charles's Law consists of the relationship between the volume and the temperature of a certain amount of ideal gas, which is kept at a constant pressure. This law is a law that says that when the amount of gas and pressure are kept constant, the quotient between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
Studying two different states, an initial state and a final state, you have:
In this case:
- P1= 50.7 kPa
- V1= 120 L
- T1= 15 C= 288 K (being 0 C= 273 K)
- P2= ?
- V2= 236 L
- T2= 10 C= 283 K
Replacing:
Solving:
P2= 25.3 kPa
<u><em>A volume of 236 L and a temperature of 10.0 ° C has a pressure of 25.3 kPa.</em></u>
<u><em></em></u>
You only can calculate the empirical formula with that information. I can not guarantee the empirical formula is going to be the same than the molecular formula. To be able to calculate the molecular formula you need the molecular mass or other information.
58.8/12= C = 4.9 => 4.9/1.96 = 2.5 => 2.5*2= 5
9.8/1= H = 9.8 => 9.8/1.96 = 5 => 5* 2= 10
31.4/16=O = 1.96 =>1.96/1.96 = 1 => 1*2 =2
empirical formula C5H10O2
33 - 15 = 18
This element is P-33