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Aleks04 [339]
3 years ago
5

The compound C2E10H12 (where E is an element) has a formula mass of approximately 144 g/mol. What is the atomic mass of E?

Chemistry
1 answer:
amid [387]3 years ago
6 0

Answer:

Explanation:

C₂E₁₀H₁₂  = 144

molecular weight of given compound

= 2 x 12 + 10 x E + 12 x 1 = 144 ( atomic weight of C = 12 , H = 1 , E = E )

24 + 10 E + 12 = 144

10 E = 108

E = 10.8

Atomic mass of E = 10.8 u .

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5 0
3 years ago
Reaction type for this equation <br> 2 AgNO3 + Cu → Cu(NO3)2 + 2 Ag
horrorfan [7]

Answer:

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6 0
3 years ago
Calculate the theoretical yield and percent yield for this experiment
coldgirl [10]

Answer:

A. Theoretical yield of KCl is 36.49g

B. Percentage yield of KCl is 90.4%

Explanation:

The balanced equation for the reaction is given below:

2KCLO3 —> 2KCl + 3O2

Next, we shall determine the mass KClO3 that decomposed and the mass KCl produce from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Molar mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g.

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

A. Determination of the theoretical yield of KCl. This is illustrated below:

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

Therefore, 60g of KClO3 will decompose to produce = (60 x 149)/245 = 36.49g of KCl.

Therefore, the theoretical yield of KCl is 36.49g

B. Determination of the percentage yield of KCl. This can be obtaine as follow:

Actual yield = 33g

Theoretical yield = 36.49g

Percentage yield =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 33/36.49 x 100

Percentage yield of KCl = 90.4%

7 0
3 years ago
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