Explanation:
For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.
The given balanced equation has been:
\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O
From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.
The mass of oxygen has been: 8.75 g,
Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight
Moles of oxygen = \rm \dfrac{8.75}{32}328.75
Moles of oxygen = 0.27 mol
Since,
1 mole Oxygen = 2 mole hydrogen
0.21 mol oxygen = 0.54 mol hydrogen
Mass of hydrogen = moles \times× molecular weight
Mass of hydrogen = 0.54 \times× 2
Mass of hydrogen = 1.08 grams.
Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.
