Answer:
a. n = 6,54 moles.
b. CH₃COOH(aq) + NaHCO₃(aq) → CH₃COONa(aq) + H₂O (l) + CO₂(g)
c. 549g of NaHCO₃
d. 7,85L of CH₃COOH
Explanation:
a. It is possible to know moles of CO₂ required to inflate the air bag using:
n = PV/RT
Where n are moles; P is pressure (1atm at room conditions); V is volume (160L); R is gas constant (0,082 atmL/molK); and T is temperature (298,15K at room conditions.
Replacing:
<em>n = 6,54 moles.</em>
b. The reaction of CH₃COOH with NaHCO₃ produce:
CH₃COOH(aq) + NaHCO₃(aq) → CH₃COONa(aq) + H₂O (l) + CO₂(g)
c. 1 mol of CO₂ is produced from 1 mol of NaHCO₃, that means 6,54moles of CO₂ are produced from <em>6,54 moles of NaHCO₃</em>. In grams:
6,54 moles NaHCO₃×
= <em>549g of NaHCO₃</em>
d. Again, you require 6,54 moles of CH₃COOH. If your acetic acid solution is 0,833M you need:
6,54moles×
= <em>7,85L of CH₃COOH</em>
<em></em>
I hope it helps!
Answer:
Heavy water is a compound that is made up of oxygen and deuterium, a heavier isotope of hydrogen which is denoted by ‘ 2 H’ or ‘D’. Heavy water is also called deuterium oxide and is denoted by the chemical formula D 2 O.
Density: 1.107 g/mL
Dipole moment: 1.87 D
Heavy Water (Deuterium Oxide): D2O
Molecular Mass: 20.02 grams/mole
Explanation:
Answer:
C. Its oxidation number increases.
Explanation:
- <em><u>Oxidation is defined as the loss of electrons by an atom while reduction is the gain of electrons by an atom</u></em>.
- Atoms of elements have an oxidation number of Zero in their elemental state.
- When an atom looses electrons it undergoes oxidation and its oxidation number increases.
- For example, <em><u>an atom of sodium (Na) at its elemental state has an oxidation number of 0. When the sodium atom looses an electrons it becomes a cation, Na+, with an oxidation number of +1 , the loss of electron shows an increase in oxidation number from 0 to +1.</u></em>
Answer : chemical reaction
Mixing an acid with a base is a common chemical reaction.
