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3 years ago

Solve the system of linear equations by substitution.

1 answer:

5 0

Y=-4.5 and x=-2
So your first “equation equals to x so then you substitute the X in the second equation with the first equation. Which would give you 3(2y+7)-2y=3 then you solve (make sure to distribute). Which would give you y=-4.5 Can you substitute your y answer in your first equation. Which would be x= 2(-4.5)+7 then your solve

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200 students in a high school senior class are surveyed about what majors they intend to declare in college.

vekshin1

Answer:

2/5

1/2

3/20

3/4

Step-by-step explanation:

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4 years ago

Latisha worked for six hours and 45 minutes how should she write that on her time card

AlexFokin [52]

Answer:

Hey there!

6 hrs 45 mins = 405 mins, or 6.75 hours.

Hope this helps :)

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3 years ago

Jack’s school bag contains 8 books each of weight 3/8 pounds, and 6 folders of weight 1/2 pound. b) What fraction of the total w

kirill115 [55]

Answer:

6 pounds

Step-by-step explanation:

3/8×8/1=24/8=3

6/1×1/2=6/2=3

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2 years ago

Question 2 of 10 What is the surface area of the rectangular pyramid below?

Ymorist [56]

Answer:

363

Step-by-step explanation:

11x11=121

((11x11)÷2)x4=11x11x2=121x2=242

121+242=363

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2 years ago

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x

konstantin123 [22]

Answer:

$f(x)=x^{3}-3x^{2} +4x-2$

Step-by-step explanation:

we know that

The conjugate root theorem states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

$f(x)=a(x-1)(x-(1+i))(x-(1-i))$

Remember that

The leading coefficient is 1

a=1

$f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2$

5 0

4 years ago

Read 2 more answers