A senior ticket costs $10, while a student ticket costs $8. You can solve this system of equations by the elimination method.
We can use x as the variable for the senior tickets, and y as the variable for the student tickets and represent it with these equations:
10x+12y=212 and 12x+14y=232
Next, multiply each entire equation by a variable so they can eliminate each other. I used 12 and -10 here so it would be 120x-120x to eliminate that variable.
12(10x+14y=212) and -10(12x+14y=232)
Our new equations are:
(120x +168y= 2544) and (-120x-140y=-2320)
You can then subtract one of the equations from the other leaving you with 28y=224 and solve it for y to get 8.
So the price of a student ticket is 8.
Pick any of the original equations and by replacing y with 8, you can solve to find x. (X is the variable we assigned for senior tickets)
10x+14(8)=212
10x+112=212
10x=212-112
10x= 100
1x=10
Answer:
-6
Step-by-step explanation:
The formula of slope Y2-Y1/X2-X1
so you actually use this formula equal to -2
10-6/X-(-4) = -2
Y=2x+2 the equation that represent the line
It would be 6 because they both have 6 in them
Answer:
Null hypothesis:
Alternative hypothesis:
And the best answer for this case is:
C. p-value
Step-by-step explanation:
Data given and notation
n represent the random sample taken
estimated proportion of interest
is the value that we want to test
represent the significance level
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion i 0.72 or no.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .
For this case the only probability that can be calculated from the statistic calculated is the p value given by:
And the best answer for this case is:
C. p-value