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kirza4 [7]
3 years ago
13

OMG this question is so weird but please take it seriously. Working together, Tom and Di ck can dig 3 holes in 6 hours. Knowing

Tom digs twice as fast as Di ck, how many hours would it take Tom, working alone, to dig 12 holes?
Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

Tom can dig 12 holes in 36 hours.

Step-by-step explanation:

Tom and Di ck dig 3 holes in 6 hours.

Tom works twice as fast as Di ck, so it is as if Tom is the same as 2 people at Di cks's speed and Di ck is as if it is 1 person at Di ck's speed. This means it is as if there are 3 people working at Di ck's speed.

Di ck working alone can dig 1 hole is 6 hours.

Tom can dig 2 holes in 6 hours.

Tom can dig 12 holes in 36 hours.

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The rotation that has this said rule is R0, 90°. And 90° is equal to –270°. 
The answers are:
R0, 90°
R0, –270°.
Additional information:
R0, 180° has the rule (x, y) → (-x, -y)
R0, 270° and R0, –90° has the rule  (x, y) → (y, -x).
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You have 2 different savings accounts. For Account​ A, the simple interest earned after 21 months is ​$13.65. For Account​ B, th
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Answer:

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P = principal

T = time in years

R = interest rate on the principal.

For account​ A, the simple interest earned after 21 months is ​$13.65. The interest rate is 3.9​% for Account A

Let y represent the principal for account B. Therefore

P = x

I = $13.65

T = 21/12 = 1.75 years

R = 3.9

Therefore

13.65 = (x × 3.9 × 1.75)/100

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For account​ B, the simple interest earned after 30 months is $40.25. The interest rate is 2.3% for Account B

Let x represent the principal for account A. Therefore

P = y

I = $40.25

T = 30/12 = 2.5 years

R = 2.3

Therefore

40.25 = (y × 2.3 × 2.5)/100

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y = 4025/5.75 = $700

The principal for account A is $200

The principal for account B is $700

For account A, interest earned in the first month is

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Account B earned the most interest in the first month(the same interest is earned every month)

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