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3 years ago

Which of the following tables represents a function? A. B. C. D.

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

In a function the x value cannot repeat

As long as no x value repeats it is considered a function

In answer choice A the x value "1" repeats therefore table a is not a function

In answer choice B no x value repeats twice. This one might be the answer however lets check the other tables just to be safe.

In answer choice C the x value "-4" repeats multiple times therefore table C is not a function

In answer choice D the x value "1" and "2" repeat therefore table D is not a function.

Thus, the answer is B

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Answer:

300

Step-by-step explanation:

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3 years ago

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It would be A. 0.65
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3 years ago

Noah has just graduated high school and has some credit card offers! The first credit card (Credit Card A) charges 18% compounde

Usimov [2.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

One evening, it snowed in several towns. The number of inches of snow the towns received are shown in the list below.

Rama09 [41]

Answer:

3/4,3/4,3/4,3/4,1,1,2,11/2,11/2,11/4,11/4

Step-by-step explanation:

we just arrange the number from the smallest to bigger

8 0

3 years ago