Step-by-step explanation:
Marcel will take 35 days, xion will take 44 days (43.75), Francesca will take 32 days, and amber will take 44 days (43.75)
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a.
b.
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:
The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days
Solving (b); The value of E when d = 30.
Substitute 30 for d in
<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
the value of x in the above equation is 7.35
So 20 toys=12 will be dolls and well 30 is ? Well, just divide 12 by 2 and you get 6 Therefore in 10 toys you will get 6 dolls Which means in conclusion if you get 30 toys, you will receive 18 dolls since 6x3 =18:)
Answer:
(P(t)) = P₀/(1 - P₀(kt)) was proved below.
Step-by-step explanation:
From the question, since β and δ are both proportional to P, we can deduce the following equation ;
dP/dt = k(M-P)P
dP/dt = (P^(2))(A-B)
If k = (A-B);
dP/dt = (P^(2))k
Thus, we obtain;
dP/(P^(2)) = k dt
((P(t), P₀)∫)dS/(S^(2)) = k∫dt
Thus; [(-1)/P(t)] + (1/P₀) = kt
Simplifying,
1/(P(t)) = (1/P₀) - kt
Multiply each term by (P(t)) to get ;
1 = (P(t))/P₀) - (P(t))(kt)
Multiply each term by (P₀) to give ;
P₀ = (P(t))[1 - P₀(kt)]
Divide both sides by (1-kt),
Thus; (P(t)) = P₀/(1 - P₀(kt))