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guapka [62]
3 years ago
11

Explain how dangerous floods can be. PLEASE HELP! GIVING BRAINLIEST

Physics
2 answers:
Sonja [21]3 years ago
8 0

Answer:

Explanation:Standing flood waters can also spread infectious diseases, contain chemical hazards, and cause injuries. Each year, flooding causes more deaths than any other hazard related to thunderstorms. The most common flood deaths occur when a vehicle is driven into hazardous flood waters.

IceJOKER [234]3 years ago
3 0
Floods can be very dangerous because they destruct almost everything it goes through and they can happen without any warning to get away!
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PLS HELP ME<br> I NEED HELP ASAP
Tanzania [10]

Answer:

  1. In order to find average velocity we use the equation:
  2. avg =  \frac{change \: in \: x}{change \: in \: time}
  3. She went from 4.0m to 16.0 m making her delta x = 12.0 m
  4. She did that in 4s
  5. Hence 12/4 = 3 m/s

8 0
3 years ago
A 0.03 in.diameter glass tube is inserted into SAE 30 oilat 60°F. The contact angle (i.e., the angle a liquid forms in contact w
Snowcat [4.5K]

Answer:

The value of capillary rise in the tube = 0.0363 cm

Explanation:

Diameter of the glass tube = 0.03 meter

Contact angle = 22 degree

We know that the capillary rise (h) in the tube is given by the formula =

h = (2 α cos β) / (d g R )

⇒ d = density of gasoline = 749 kg / m^{3}

   β = 22 degree

   R = radius of the tube = 0.015 m

   α = surface tension of gasoline = 0.0216 N / m

   cos 22 = 0.927

Put all the values in the above formula we get

⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)

⇒ h = 0.0363 cm

This is the value of capillary rise in the tube.

7 0
3 years ago
"An alpha particle (He2+) with a velocity of 2.6x106m/scrosses a uniform magnetic field at an angle of 37.0°to the field lines a
sergey [27]

Answer:

B = 5.59x10⁹ T

Explanation:

The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:

F = qvBsin(\theta)

<u>We have:</u>

F = 1.4x10⁻³ N

v = 2.6x10⁶ m/s

θ = 37.0°

q = 2*p = 2*1.6x10⁻¹⁹ C

Hence, the strength of the magnetic field is:

B = \frac{F}{qvsin(\theta)} = \frac{1.4 \cdot 10^{-3}}{1.6 \cdot 10^{-19} C*2.6 \cdot 10^{6}*sin(37)} = 5.59 \cdot 10^{9} T

Therefore, the strength of the magnetic field is 5.59x10⁹ T.

I hope it helps you!

7 0
3 years ago
Can plz anyone solve this​
neonofarm [45]

Answer:

1 Ohm

Explanation:

Resistance: Voltage/Current

R: 1.5/ 1.5 = 1 Ohm

6 0
3 years ago
The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol
Lesechka [4]

Answer:

\Delta V = 0.053 A

Explanation:

Electric field in a given region is given by equation

E = \frac{A}{r^4}

as we know the relation between electric field and potential difference is given as

\Delta V = -\int E. dr

so here we have

\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

r_1 = 1.71 m  and r_2 = 2.89 m

so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

8 0
3 years ago
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