Answer:
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Answer:
The force is 
Explanation:
The moment of Inertia I is mathematically evaluated as

Substituting
for M(Mass of the wheel) and
for
(Radius of wheel)


The torque on the wheel due to net force is mathematically represented as

Substituting 135 N for
(Force acting on sprocket),
for
(radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of
and this torque can also be represented mathematically as

Now equating the two equation for torque
Making F the subject

Substituting values


Words less true are seldom if ever spoken.
Answer:
X₃₁ = 0.58 m and X₃₂ = -1.38 m
Explanation:
For this exercise we use Newton's second law where the force is the Coulomb force
F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
Since all charges are of the same sign, forces are repulsive
F₁₃ = k q₁ q₃ / r₁₃²
F₂₃ = k q₂ q₃ / r₂₃²
Let's find the distances
r₁₃ = x₃- 0
r₂₃ = 2 –x₃
We substitute
k q q / x₃² = k 4q q / (2-x₃)²
q² (2 - x₃)² = 4 q² x₃²
4- 4x₃ + x₃² = 4 x₃²
5x₃² + 4 x₃ - 4 = 0
We solve the quadratic equation
x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2 5
x₃ = [-4 ± 9.80] 10
X₃₁ = 0.58 m
X₃₂ = -1.38 m
For this two distance it is given that the two forces are equal