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liubo4ka [24]
3 years ago
7

HELP!!! HURRY DUE BY 4:30!!!

Physics
2 answers:
Ipatiy [6.2K]3 years ago
4 0
Work = force * distance. 
<span>You must produce twice as much energy as we are lifting the weight twice as high. </span>
<span>But because you aren't increasing the force, you need to increase the length of the ramp instead. </span>
<span>The new length will be twice as great as the previous length. </span>
<span>So 8 metres is required. </span>

Hope this helps.
Daniel [21]3 years ago
4 0
Its 8 meters, 
:DDDDDDDDDDDDD
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SashulF [63]

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2 years ago
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
Katyanochek1 [597]

Answer:

The force is F = 1041.7N

Explanation:

The moment of Inertia I is mathematically evaluated as

               I = MR_A^2

Substituting  1.9kg for M(Mass of the wheel) and \frac{66cm}{2} * \frac{1m}{100cm} = 0.33m for R_A(Radius of wheel)

              I = 1.9 * 0.33^2

                = 0.207kgm^2

The torque on the wheel due to net force is mathematically represented as

                      \tau = FR_B  - F_rR_A

Substituting  135 N for F_r (Force acting on sprocket),\frac{8.7cm}{2} * \frac{1m}{100cm} = 0.0435m for R_B (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

                     \tau = F (0.0435) - 135 (0.33)

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of \alpha  = 3.70 rad/s^2 and this torque can also be represented mathematically as

                   \tau = \alpha I

Now equating the two equation for torque

                                F (0.0435) - 135 (0.33) = \alpha I    

Making F the subject

                     F = \frac{\alpha I + (135*0.33) }{0.0435}

Substituting values

                  F = \frac{(3.70 * 0.207)  + (135*0.33)}{0.0435}

                       = 1041.7N

4 0
2 years ago
Displacement is the change in velocity of an object.<br><br> True or false
Elden [556K]

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7 0
3 years ago
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What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up
alexandr1967 [171]

Answer:

i think it's 1400

Explanation:

w = Force x displacement

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3 0
3 years ago
Two charged particles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged par
Murrr4er [49]

Answer:

X₃₁ = 0.58 m  and  X₃₂ = -1.38 m

Explanation:

For this exercise we use Newton's second law where the force is the Coulomb force

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        F₁₃ = F₂₃

Since all charges are of the same sign, forces are repulsive

        F₁₃ = k q₁ q₃ / r₁₃²

        F₂₃ = k q₂ q₃ / r₂₃²

Let's find the distances

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         r₂₃ = 2 –x₃

We substitute

      k q q / x₃² = k 4q q / (2-x₃)²

      q² (2 - x₃)² = 4 q² x₃²

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We solve the quadratic equation

        x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2  5

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       X₃₂ = -1.38 m

For this two distance it is given that the two forces are equal

7 0
3 years ago
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