Question

A 0.03 in.diameter glass tube is inserted into SAE 30 oilat 60°F. The contact angle (i.e., the angle a liquid forms in contact with a solid) of oilwith a glass surface is 22°. Determine the capillary rise of gasolinein the tube

Answer 1

Answer:

The value of capillary rise in the tube = 0.0363 cm

Explanation:

Diameter of the glass tube = 0.03 meter

Contact angle = 22 degree

We know that the capillary rise (h) in the tube is given by the formula =

h = (2 α cos β) / (d g R )

⇒ d = density of gasoline = 749 kg / $m^{3}$

   β = 22 degree

   R = radius of the tube = 0.015 m

   α = surface tension of gasoline = 0.0216 N / m

   cos 22 = 0.927

Put all the values in the above formula we get

⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)

⇒ h = 0.0363 cm

This is the value of capillary rise in the tube.