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3 years ago

12

Like and subscribe to coryshyper please guys! He is so desperate please that’s all I ask for take 8 seconds out of your day to s

upport him please!

2 answers:

fiasKO [112]3 years ago

5 0

Answer:

When I get the chance I will :))

Step-by-step explanation:

Love the pfp btw!!!!!!

LenKa [72]3 years ago

4 0

Ok ill try to do that :)

You might be interested in

Please Help! i need explanations too. Thank you

Lady bird [3.3K]

Answer:

Step-by-step explanation:

The most important thing to remember when solving equations is whatever you do to one side, you must do to the other.

1. (15m + 3)/2 = -6

First, we can simplify by removing the fraction:

15m + 3 = -6 x 2 (multiply both sides by 2)

15m + 3 = -12

15m = -12 - 3 (subtract by 3 on both sides)

15m = -15

m = -15/15 (divide by 15 on both sides)

m = -1

2. 3/2x -15 = -12

first, we'll add both sides by 15

2/3x = -12 + 15

2/3x = 3

x = 3/(2/3) both sides divided by 2/3, just put that in your calculator, if you can't do it in your head

x = 4 1/2

3. -7x + 3 = -15/2

We can remove the fraction by doing the same thing as in the first question.

2(-7x + 3) = -15

-14x + 6 = -15

14x = -15 -6

14x = -21

x = -21/14

x = -1 1/2

4. 4x + 1/2(12x + 2) = 3

First we need to simplify by expanding:

4x + 6x + 1 = 3

Now we collect the like terms to further simplify the equation

10x + 1 = 3

10x = 3 - 1

10x = 2

x = 2/10

x = 1/5

5. 3/2(x + 8) = 6x

We're going to start by removing the brackets, this time by multiplying the fraction on both sides:

x + 8 = 6x / (3/2)

x + 8 = 4

x = 4 - 8

x = -4

Now the questions, some of them are personal, so I won't be able to answer them for you, but I can try with the others:

These types of problems are fractional equations, and you need to find the value of the variable, which in this case was x.

I'm not sure what information you already know, so you'll have to think on that one.

Strategies you could use or try include multiplying, dividing, subtracting and adding on both sides as well as collecting like terms and expanding.

Hope this helped,

Cate

5 0

3 years ago

What is the minimum and maximum whole number side length for △ABC with given side lengths of 9 cm and 11 cm? Please explain why

Gwar [14]

Answer:

Step-by-step explanation:

We would assume that triangle ABC is a right angled triangle. This means that we can apply Pythagoras theorem in determining the unknown side length.

For the case of the minimum side length, we would assume that the unknown length, L is one of the shorter legs of the triangle. By applying Pythagoras theorem, it becomes

11² = 9² + L²

L² = 121 - 81 = 40

L = √40 = 6.32

For the case of the maximum side length, we would assume that the unknown length, L is one of the hypotenuse of the triangle. By applying Pythagoras theorem, it becomes

L² = 9² + 11²

L² = 81 + 121 = 202

L = √202 = 14.21

The minimum side length is 6.32 and the maximum side length is 14.21

5 0

3 years ago

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em> and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$

and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But

$\bf P(X$

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0

3 years ago

Solve with explanation pls Simplify the expression -2x - 4y + 10 + 2x - 2y - 6. Type your answer in without spaces

Natalija [7]

Answer

-6y+4

4Step-by-step explanation:

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-2x-4y+{\color{#c92786}{10}}+2x-2y{\color{#c92786}{-6}}

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5 0

2 years ago

Read 2 more answers

A motorboatcan go 8 miles downstream on a river in 20 minutes. It takes 30 minutes for the boat to go upstream the same 8 miles.

True [87]

<span>Let m = speed of motorboat
and c = speed of current
.
When going downstream, current speed is added to boat speed -- and, the total speed is "8 miles downstream in 20 minutes"
.
To convert to "miles per hour" we multiply by 60 mins per 1 hour:
(8 miles/20 mins) * (60 mins/1 hour) = 24 mph
.
This gives us our first equation (1):
m+c = 24
.

When going upstream, the boat speed is reduced by the current -- and, the total speed is "8 miles in 30 minutes".
To convert to "miles per hour" we multiply by 60 mins per 1 hour:
(8 miles/30 mins) * (60 mins/1 hour) = 16 mph
.
This gives us our second equation (2):
m-c = 16
m = 16+c
.
Plug the above into equation 1 and solve for c:
m+c = 24
16+c+c = 24
16+2c = 24
2c = 8
c = 4 mph </span>

5 0

3 years ago