Answer:
b could be -1 or 0
Step-by-step explanation:
f(x) = 3x^2 +bx+2
if it has no real roots, the discriminant must be less than zero
b^2 -4ac <0
a=3 b=b c=2
b^2 - 4(3)(2) <0
b^2 - 24 <0
b^2 < 24
Taking the square root of each side
b< 2 sqrt(6) and b > 2 sqrt(6)
b could be -1 or 0
The area of a square is the length of a side squared ( Area= Side^2)
when the area is known take the square root of the area to find the length of the side:
Side = sqrt(area)
Side = sqrt(75)
side = 8.7
the length is between 8 and 10
the answer is B
30.00x3=90.00$+25.00$=115.00$ so it has to be 115.00)
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Answer:
96
Step-by-step explanation:
First we need to know the mean of the Steve's scores on 6 of his tests. Given the six scores as 92, 78, 86, 92, 95, and 91.
Mean = sum of the scores/Total test taken
Mean = 92+78+86+92+95+ 91/6
Mean = 534/6
Mean = 89
If he took the seventh test and the mean score is raised by 1 them the new mean will be expressed as;
New mean = 92+78+86+92+95+ 91+x/7 = 89+1
Where x is the new score. Note that of a new score is added, the total year taken will also change to 7
To get x;
92+78+86+92+95+ 91+x/7 = 89+1
92+78+86+92+95+ 91+x/7 = 90
534+x/7 = 90
Cross multiply
533+x = 90×7
533+x = 630
x = 630-534
x = 96
Hence the score of the seventh test is 96
