To find the area of the curve subject to these constraints, we must take the integral of y = x ^ (1/2) + 2 from x=1 to x=4
Take the antiderivative: Remember that this what the original function would be if our derivative was x^(1/2) + 2
antiderivative (x ^(1/2) + 2) = (2/3) x^(3/2) + 2x
* To check that this is correct, take the derivative of our anti-derivative and make sure it equals x^(1/2) + 2
To find integral from 1 to 4:
Find anti-derivative at x=4, and subtract from the anti-derivative at x=1
2/3 * 4 ^ (3/2) + 2(4) - (2/3) *1 - 2*1
2/3 (8) + 8 - 2/3 - 2 Collect like terms
2/3 (7) + 6 Express 6 in terms of 2/3
2/3 (7) + 2/3 (9)
2/3 (16) = 32/3 = 10 2/3 Answer is B
Lt,[F(x)+2g(x)] x that’s the answer
So we have to use the distributive property:
We ll get -12x-9-2x+5+18x-24
Now we have to combine like terms
-12-2x+18x=4x
-9+5-24=-28
Therefore our answer is:
Y=4x-28
Answer: yea
Step-by-step explanation:
First place a point at (0,5) since the y-intercept is 5, then count 6 units down and 1 unit right. Then place a point until all points have been placed
