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Vedmedyk [2.9K]
3 years ago
12

What is the difference between dominant and recessive traits? ​

Biology
2 answers:
devlian [24]3 years ago
6 0

Answer:

Dominant trait is the trait that the offspring are more likely to have, like if a dominant trait is to have green eyes and the recessive trate is blue eyes, then the offspring are more likely to have green eyes, but its likely to have blue eyes too.

Dominant traits show up more than the recessive trait, because its stronger than the recessive trait.

Explanation:

AfilCa [17]3 years ago
6 0

Answer:

Dominant traits are traits that are always expressed when the connected allele is dominant. This is for even if only one of the copy of the dominant traits exist. Dominant traits are always written in capital letters. An example of dominants traits would be BB or Bb.

Recessive traits are traits that are only expressed if both of the alleles are recessive. A recessive trait is always written in a lowercase letter. An example of recessive traits would be "bb".

Also, Dominant traits are traits that are more common to people. It is strong.  For example, if you are right handed, that is a dominant trait. Being right handed is a common thing in this world. 90% of the world's population is right handed.

On the other hand, recessive traits are traits that are rare to people. It is weak. For example, if you are left handed, that is a recessive trait. Being left handed is a rare thing for people in this world. Only 10% of the world's population is left handed.  

Hope I helped you! If so, have a great day!

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In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
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Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
3 years ago
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