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2 years ago

A $280 suit is marked down by 30%. Find the sale price. The sale price is $

Mathematics

2 answers:

storchak [24]2 years ago

3 0

Answer:

Step-by-step explanation:

30% * $280

$\frac{}{100}$

= 84

So, the sale price is $84

umka21 [38]2 years ago

3 0

Answer:

186

Step-by-step explanation:

.7×280.............................

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

The lead statue of the Korean War Memorial in Washington DC casts a 43.5 inch shadow at the same time a nearby tourist casts a 3

AfilCa [17]

Answer:

The lead statue is 87 inches tall

Step-by-step explanation:

Let

x ----> the height of the lead statue

using proportion

we know that

The height of the lead statue divided by the length of his shadow must be equal to the height of the tourist divided by the length of his shadow.

$\frac{x}{43.5}=\frac{64}{32}\\\\\frac{x}{43.5}=2\\\\x=2(43.5)\\\\x=87\ in$

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2 years ago

The length of the hypotenuse of a 30-60 -90 triangle is 14 units. what is the length of the short leg

kifflom [539]

Recall that the short leg is the side opposite the 30 degrees angle. And the ratio of the short leg to the hypotenuse is 1:2.

Let the length of the short leg be x, then,

$\cfrac{x}{14}=\cfrac{1}{2}\\ \\\Rightarrow2x=14\\ \\\Rightarrow x=\cfrac{14}{2}=7$

6 0

3 years ago

Please help thank you! will give brainliest!

VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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1 year ago

Solve for missing variable d=rt, r=57, t=4

____ [38]

D=228

when 2 numbers or variables are next to eachother it means you need to multiply. So in this case r=57 and t=4 and we mulitply. 57 x 4 = 228. So the answer is 228. Hope this helps and have a great day!

8 0

2 years ago