Engineers want to design brakes that will reduce stopping distances by 10%. How would this change the equation relating speed s,
friction f, and stopping distance d?
s=√30fd
1 answer:
For the answer to the question above, we will use this formula to solve this problem
<span>d = kv^2 </span>
<span>plugging in, </span>
<span>4.2 = k*10^2 </span>
<span>k = 0.042 </span>
<span>d = 0.042v^2 </span>
<span>the revoised equation will be </span>
<span>d = 0.9*0.042v^2 , i.e. </span>
<span>d = 0.0378v^2
I hope my answer helped you</span>
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