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krok68 [10]
3 years ago
7

Please help, this is due soon!

Mathematics
1 answer:
Oliga [24]3 years ago
6 0
Before outlier : 7.25
After outlier : 4

7.25 - 4 = 3.25

So the mean decreases by 3.25 when the outlier is removed.
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Kyle’s account was overdrawn so that the account showed $9 less than zero. Kyle deposited $25 in the account. The next day he wi
SOVA2 [1]
X=(-9+25)-10 I think
7 0
3 years ago
Read 2 more answers
ABC is a right angled triangle right angled at B . A circle with centre O inscribed in the triangle . AB=6CM BC=8CM . Find the r
Vikki [24]

Answer:

Radius = 2 cm.

Step by step explanation:

By the Pythagoras theorem  the third side of the triangle

= sqrt (6^2 + 8^2)cm = sqrt100 = 10cm.

The formula for the radius of the circle is

r = sqrt [ (s - a)(s-b)(s-c)/ s ]  where a,b,c are side lengths and s = the semi perimeter.

Here s = ( 6+8+10) / 2 = 12

So the radius r  

= sqrt [ (12-6)(12-8)(12-10)/ 12 ]

= sqrt 4

= 2 (answer).

3 0
3 years ago
The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Grey tea t
bekas [8.4K]
<span>75 lbs of Earl Grey 225 lbs of Orange Pekoe Some definitions. E = number of pounds of Earl Grey (300-E) = number of pounds of Orange Pekoe Expression for selling price of new blend P=300*4.5 "there is to be no difference in revenue from selling the new blend versus selling the other types." so P = 6E + 4(300-E) Set them equal to each other, then solve for E 300*4.5 = 6E + 4(300-E) 1350 = 6E + 1200 - 4E 150 = 6E - 4E 150 = 2E 75 = E So 75 lbs of Earl Grey was used and 300-75 = 225 lbs of Orange Pekoe</span>
5 0
3 years ago
Find the area under the standard normal curve between z = −2.57 and z = 1.27. Round your answer to four decimal places, if neces
dexar [7]
P(-2.57 ≤ Z ≤ 1.27) = P(Z ≤ 1.27) - P(Z ≤ -2.57)

P(Z ≤ 1.27) = 0.8980
P(Z ≤ -2.57) = 1 - P(Z ≤ 2.57) = 1 - 0.99488 = 0.00512

P(-2.57 ≤ Z ≤ 1.27) = 0.8980 - 0.00512 = 0.89288
0.8929 (4 d.p.)
4 0
3 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
babymother [125]

Answer:

1. b. 14.6 ± 7.38

2. b. 3.43

3. b. 0.01 < P-value < 0.05

4. b. There is sufficient evidence to reject the null hypothesis.

Step-by-step explanation:

The hypothesis test is used to test the null hypothesis against the alternative hypothesis. The p value of the test determines whether to accept or reject the null hypothesis. In the given scenario the p value is less than 0.05 so there is sufficient evidence against the null hypothesis in favor of alternative hypothesis.

5 0
3 years ago
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