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algol13
3 years ago
8

Find m∠P. explanation is optional

Mathematics
1 answer:
prisoha [69]3 years ago
6 0
Answer is 60
The angle that is marked with “120” is equal to the one that’s on the opposite corner.
And to find angle P ur gonna need to find 180-120 cuz they’re supplementary angles. (Meaning that they’re equal to 180)
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11 more than a number q is negative 15 ; Solve for the variable.
Cloud [144]

Answer:

q = -26

Step-by-step explanation:

Set up an equation where q is the unknown number:

q + 11 = -15

Solve for q by subtracting 11 from both sides:

q + 11 = -15

q = -26

4 0
3 years ago
How do i solve v=pi/3*r (squared)h for h
Colt1911 [192]
V=\dfrac{\pi}{3}\cdot r^2h\ \ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |\divide\ both\ sides\ by\ \pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}
3 0
3 years ago
What is the interest you will pay if you borrowed $120 at 5% interest for 6 years?
kobusy [5.1K]

Answer:

Hope this helps!

Step-by-step explanation:

We will need the loan payment formula:

That formula is really complex and we expect you to solve it.

Your monthly payment would be $1.93 per month for 6 years making the TOTAL loan cost 1.93 * 12 * 6 = 138.96

Since the principal you borrowed is $120 the total interest =

(138.96 minus 120.00) which equals $18.96

6 0
3 years ago
Read 2 more answers
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
3 years ago
The area of the larger circle is??
nevsk [136]

radius of small circle = 16 m

radius of large circle is doubled so it will be 32 m


Area of the larger circle = π x 32^2 = 1,204π m^2


answer

1,204π m^2

7 0
3 years ago
Read 2 more answers
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