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joja [24]
2 years ago
15

Obtain the required confidence interval for the difference between two population proportions. Assume that independent simple ra

ndom samples have been selected from the two populations. A survey found that 37 of 74 randomly selected women and 47 of 74 randomly selected men follow a regular exercise program. Find a 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program. Group of answer choices
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

The 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

Step-by-step explanation:

The formula for confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

From the question

We have two groups.

Group 1 = For women

A survey found that 37 of 74 randomly selected women

p1 = x/n1

n1 = 74

x1 = 37

p1 = 37/74

p1 = 0.5

Group 2 = For Men

A survey found out that 47 of 74 randomly selected men follow a regular exercise program

p2 = x/n1

n2= 74

x2 = 47

p2 = 47/74

p2 = 0.6351351351 ≈ 0.635

z = z score for 95% Confidence Interval = 1.96

The confidence interval for the difference between the proportions is given as:

p1 - p2 ± z × √p1 (1 - p1)/n1 + p2(1 - p2)/n2

0.5 - 0.635 ± 1.96 × √0.5 (1 - 0.5)/74 + 0.635(1 - 0.635)/74

-0.135 ± 1.96 × √(0.5 × 0.5)/74 + (0.635× 0.365)/74

-0.135 ± 1.96 × 0.08068750209663572

-0.135 ± 0.158147504109406

Hence:

= -0.135 - 0.158147504109406

= -0.2931475041

Approximately = -0.293

= -0.135 + 0.158147504109406

= 0.0231475041

Approximately = 0.023

Therefore, the 95% confidence interval for the difference between the proportions of women and men who follow a regular exercise program = ( -0.293, 0.023)

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The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
Without graphing classify each system as independent dependent or inconsistent -x -y=7<br> 5x-5y=5
jek_recluse [69]

Answer:

Is a consistent independent system

Step-by-step explanation:

we have

-x-y=7 -----> isolate the variable y

y=-x-7 ----> equation A

5x-5y=5 -----> isolate the variable y

y=x-5 ---> equation B

Compare equation A and equation B

We can affirm that

The slopes are not equal ( so the lines are not parallel)

The lines are different

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so

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therefore

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2 years ago
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jasenka [17]

Answer:

3. They're adding by 5 so,

Step-by-step explanation:

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Explanation:
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