The solution of the equation is x = 0 and y = 8.
Given
The system of equation is;
![\rm -5x + 5y = 40\\\\4x + 3y = 24](https://tex.z-dn.net/?f=%5Crm%20-5x%20%2B%205y%20%3D%2040%5C%5C%5C%5C4x%20%2B%203y%20%3D%2024)
<h3>How to find the solution to a system of equations?</h3>
Any system of equations can be solved in different methods. To solve a system of equations in 2 variables, we need at least 2 equations following all the steps given below.
From equation 1
![\rm -5x+5y=40\\\\5y=40+5x\\\\y = \dfrac{40+5x}{5}\\\\y = 8+x](https://tex.z-dn.net/?f=%5Crm%20-5x%2B5y%3D40%5C%5C%5C%5C5y%3D40%2B5x%5C%5C%5C%5Cy%20%3D%20%5Cdfrac%7B40%2B5x%7D%7B5%7D%5C%5C%5C%5Cy%20%3D%208%2Bx)
Substitute the value of y in equation 2
![\rm 4x+3y=24\\\\4x+3(8+x)=24\\\\4x+24+3x=24\\\\7x=24-24\\\\7x=0\\\\x=0](https://tex.z-dn.net/?f=%5Crm%204x%2B3y%3D24%5C%5C%5C%5C4x%2B3%288%2Bx%29%3D24%5C%5C%5C%5C4x%2B24%2B3x%3D24%5C%5C%5C%5C7x%3D24-24%5C%5C%5C%5C7x%3D0%5C%5C%5C%5Cx%3D0)
Substitute x = 0 in the equation 1
![\rm -5x+5y=40\\\\-5(0)+5y=40\\\\5y=40\\\\y=\dfrac{40}{5}\\\\y=8](https://tex.z-dn.net/?f=%5Crm%20-5x%2B5y%3D40%5C%5C%5C%5C-5%280%29%2B5y%3D40%5C%5C%5C%5C5y%3D40%5C%5C%5C%5Cy%3D%5Cdfrac%7B40%7D%7B5%7D%5C%5C%5C%5Cy%3D8)
Hence, the solution of the equation is x = 0 and y = 8.
To know more about the System of equation click the link given below.
brainly.com/question/12895249
Do a vediagram and tell how they are different like the are both odd... and so forth
Answer:
n(A) = 3
n(B) = 6
-6 ∈ A => True
-14 ∈ A => False
k ∈ B=> True
Q∈B = >False
Step-by-step explanation:
Given
A is the set of integers greater than - 7 and less than - 3
B={c, h, j, k, v, y}
For set A:
The integers greater than -7 will be -6,-5 ....
As the set has integers less than -3, the set will be:
![A = \{-6,-5,-4\}](https://tex.z-dn.net/?f=A%20%3D%20%5C%7B-6%2C-5%2C-4%5C%7D)
<u>Cardinalities:</u>
Cardinality is the number of elements in the set.
So,
![n(A) = 3\\n(B) = 6](https://tex.z-dn.net/?f=n%28A%29%20%3D%203%5C%5Cn%28B%29%20%3D%206)
Now for the statements:
-6 ∈ A True as -6 is a member of set A
-14 ∈ A False as -14 is not a member of A
k ∈ B True
Q∈B False
Hence,
n(A) = 3
n(B) = 6
-6 ∈ A => True
-14 ∈ A => False
k ∈ B=> True
Q∈B = >False
If you isolate the variable and divide each side by factors that don't contain the variable, it'll be solved as x = -12
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I hope this helps, as always. I wish you the best of luck and have a nice day..