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Ainat [17]
3 years ago
15

Select the statement that describes the expression 7+2n

Mathematics
2 answers:
asambeis [7]3 years ago
7 0
C cuz it can not be others. See the “ +” in the middle for the numbers?
sineoko [7]3 years ago
6 0

c

because 7+2n

sum is addition

2n is multiplication

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A= 5 and c = 13 what does b =
Maru [420]
Uh it can really be anything. You should try and be more specific: see if you did the whole problem.
8 0
3 years ago
Read 2 more answers
the area of maddies square garden is 450 square feet. she has purchased 92 feet of fence. is this the right amount of fence for
Keith_Richards [23]

Answer:

Not the right amount.

Step-by-step explanation:

A square has 4 sides so 92/4 to divide it evenly is 23.

23 times 23 for the are is 529 which is not equal to 450.

3 0
3 years ago
Compared to its 'parent' function f(x)=x^2, describe the changes if f(x)=-x^2-3
Morgarella [4.7K]

Answer:

It is inverted and shifted down 3 units.

Red is f(x) = x^2

Purple is f(x) = -x^2 -3

Step-by-step explanation:

5 0
3 years ago
(01.03. 106, 1.08 HC)
zlopas [31]

Answer:

  A) see attached for a graph. Range: (-∞, 7]

  B) asymptotes: x = 1, y = -2, y = -1

  C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

<h3>Part A</h3>

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

  \dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

__

<h3>Part B</h3>

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

__

<h3>Part C</h3>

The end behavior is defined by the horizontal asymptotes:

  for x → -∞, y → -2

  for x → ∞, y → -1

7 0
1 year ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%20%5Cfrac%7B%20%7Bx%7D%5E%7Ba%20%2B%20b%7D%20.%20%7Bx%7D%5E%7Bb%20%2B%20c%7D%20
kozerog [31]

Step-by-step explanation:

\bf \underline{Solution-} \\

We have to simplify the given expression.

\rm =  \dfrac{ {x}^{a + b} \cdot {x}^{b + c} \cdot {x}^{c + a}  }{ {x}^{a} \cdot {x}^{b} \cdot {x}^{c} }

We know that:

\rm \longmapsto {x}^{a} \times  {x}^{b}  =  {x}^{a + b}

\rm \longmapsto \dfrac{ {x}^{a} }{ {x}^{b} } =  {x}^{a -  b}

Therefore, we get:

\rm =  \dfrac{ {x}^{(a + b) + (b + c) + (c + a)}}{ {x}^{a + b + c} }

\rm =  \dfrac{ {x}^{2(a + b+ c)}}{ {x}^{a + b + c} }

\rm = {x}^{2(a + b+ c) - (a + b + c)}

\rm = {x}^{a + b + c}

7 0
2 years ago
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