This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
x= number of tickets bought
y= total
44x+12=y
Answer:
there have answer use solutions problem or write in note
Step-by-step explanation:
maybe if I can answer
Answer:
0.3 kg : 5 kg
Step-by-step explanation:
just simplified
BRAINLIEST PLS!
Answer:
Cost of small box of oranges = 7
Cost of small box of oranges = 13
Step-by-step explanation:
Step 1) Let the cost of small box of oranges = x
Let the cost of small box of oranges = y
Step 2)
Equation 1) Matt sells 3 small boxes and 14 large boxes for Php. 203
3x + 14y = 203 -------------------(I)
Equation 2) Ming sells 11 small boxes and 11 large boxes for Php. 220
11x + 11y = 220 ----------------(II)
Step 3:
Multiply equation (I) by 11 and equation (II) by (-3).
(I)*11 33x + 154y = 2233
(II)*(-3) <u>-33x - 33y = -660 </u> {Now add and x will be eliminated}
121y = 1573
y = 1573/121
y = 13
Substitute y = 13 in equation (II)
11x + 11*13 = 220
11x + 143 = 220
11x = 220 - 143
11x = 77
x = 77/11
x = 7
