Answer:
isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.
Step-by-step explanation:
Let 
denote a set of elements. 
would denote the set of all ordered pairs of elements of 
.
For example, with 
, 
and 
are both members of . However, 
because the pairs are ordered.
A relation on is a subset of . For any two elements
, 
if and only if the ordered pair 
is in 
.
A relation on set is an equivalence relation if it satisfies the following:
- Reflexivity: for any
, the relation needs to ensure that 
(that is: 
.)
- Symmetry: for any , if and only if
. In other words, either both and 
are in , or neither is in .
- Transitivity: for any
, if and 
, then 
. In other words, if and 
are both in , then 
also needs to be in .
The relation (on ) in this question is indeed reflexive. 
, 
, and 
(one pair for each element of ) are all elements of .
isn't symmetric. 
but 
(the pairs in 
are all ordered.) In other words, 
isn't equivalent to 
under even though 
.
Neither is transitive. 
and 
. However, . In other words, under relation , 
and 
does not imply 
.
Answer:
x = 1?
Step-by-step explanation:
I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think
if f(x) = -5x + 1 when f(x) = 6,
replace f(x) with 6 so,
6 = 5x + 1
1 - 6 = 5x + 1 - 1
(subtract one on both sides to isolate the variable)
5 = 5x
5/5 = 5x/5
(to Actually isolate the variable lol
1 = x or x = 1
I believe is the answer? please comment if I'm wrong
*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD
the correct answer would be A. 8^-12
8^2 /8^16 = 1/8^14 = 2.27373*10^-13
8^-12 = 1.45519*10^-11
which are equal so answer is A
Answer:
Step-by-step explanation:
Explanation: The probability of rolling a 2 on a 6-sided dice is 16 . The probability of rolling two 2s on two 6-sided die is, by the multiplication principle, 16×16=136 .
