In order to solve this let us for at assume that the value of the width is X. Therefore the length will be x+5.
We can now write an equation:
(X+5) + (X+5) + X + X = 58
Combining like terms we should get
4X + 10 = 58
Now subtract 10 from both sides to get
4x = 48
Divide by 4 now and you should get
X = 12
Now we know the value of X and therefore the width.
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Answer:
A, C
Step-by-step explanation:
Let's use a different benchmark for this: 1/2. Half of 5 is 2 1/2, so 3/5 is clearly <em>bigger</em> than 1/2 (since 3 is bigger than 2 1/2). Half of 3 is 1 1/2, so 1/3 is clearly <em>smaller</em> than a half (since 1 is smaller than 1 1/2). We have
1/3 < 1/2 < 3/5
Which, of course, implies that <em>1/3 is less than 3/5</em>, and by being smaller, <em>1/3 is closer to 0 than to 1</em>.
Sixth grade
Because if you divide their total profit by the total amount of hours they worked, you would find that the sixth grade's income per hour is the highest.
Sixth grade: 170÷5=34
Seven grade: 112÷4=28
Eighth grade: 192÷6=32
