(5 radical 2)^2 =
5^2 × (radical 2)^2 =
25 × 2 = 50
20 + 4 + 3/10 + 5/100 + 7/1000
After rotation the output for point C´ would be ( - 2 . -3 ). There is also a graph showing rotation in the attachment.
My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find. It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A] I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
The correct answer would be 2y^5
