All categories

3 years ago

What is the difference between a wave and a medium?

Physics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

Mediums in which the speed of sound is different generally have differing acoustic impedances, so that, when a sound wave strikes an interface between

Explanation:The propagation of a wave through a medium will depend on the properties of the medium. For example, waves of different frequencies may travel

You might be interested in

Construct a parallel-plate capacitor where a second line of charges equal in size and opposite in charge are placed below the li

Ymorist [56]

Answer:

Pls refer to attached file

Explanation:

8 0

4 years ago

1.) Calculate the work done in lifting a 200 N couch a distance of 1.3 m from a loading ramp.

Free_Kalibri [48]

Explanation:

work = force ×distance

1 w = ? f= 200 d= 1.3

w = f ×d

=200×1.3

= 269 joule

2 w=? f=40. d=6

w= 40/6

= 240 joule

3. w=? m=254. f= ? d=3

w=f=mg. f= 254×10. f= 2540

w=f×d

=2540×3

= 7620 joule

8 0

3 years ago

Read 2 more answers

Aril does 1800 J of work to get a canoe moving from rest. April and the canoe have a mass of 70 kg.

wolverine [178]

a) KE=energy required to make them move=1800J

b) KE=1/2*mv^2, so $v=\sqrt{\frac{2KE}{m}}=7.17$ J

4 0

3 years ago

Read 2 more answers

While water skiing behind her father’s boat, Letty is pulled at constant speed by a force of 164 N from the tow rope that makes

kap26 [50]

Answer:

0.265

Explanation:

Draw a free body diagram. There are four forces:

Normal force Fn pushing up.

Weight force mg pulling down.

Tension force T at an angle θ.

Friction force Fn μ pushing left.

Sum the forces in the y direction:

∑F = ma

Fn + T sin θ − mg = 0

Fn = mg − T sin θ

Sum the forces in the x direction:

∑F = ma

T cos θ − Fn μ = 0

Fn μ = T cos θ

μ = T cos θ / Fn

μ = T cos θ / (mg − T sin θ)

Given T = 164 N, θ = 10.0°, m = 65.0 kg, and g = 9.8 m/s²:

μ = (164 N cos 10.0°) / (65.0 kg × 9.8 m/s² − 164 N sin 10.0°)

μ = 0.265

7 0

3 years ago

. Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connecte

Umnica [9.8K]

Given :

Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.

To Find :

Will the heat produced in both the cases be equal.

Solution :

Heat released is given by :

H = i²Rt

Here, R is resistance and is given by :

$R = \dfrac{\rho L}{A}$

So,

$H = i^2\times \dfrac{\rho L}{A} t\\\\H = \dfrac{i^2\rho Lt}{A}$

Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.

So, heat produced by Reem's wire is more than Nain one.

Hence, this is the required solution.

7 0

3 years ago