Potential if it is off or kinetic energy when its on
Answer:
1.25Hz
Explanation:
For waves on a string, the second harmonic is obtained from;
2fo = 1/l √T/M
Where;
l = length of the string
M= mass in kilograms
T = tension in the string
2fo = 1/2√5/0.8
2f0 = 1.25Hz
<span>Whenever I have problems with the magnetic field strength of an electromagnet people tell to use a finer wire, I have some, its thickness is not more then the thickness of a hair, but whenever I use it, I have difficulty in connecting it with the battery because it's so thin it easily breaks off, and when I turn on the switch, it burns up instantly, maybe I am not using enough length of it.</span>
Kinetic energy can be solved by using the following formula: Kinetic energy = (1/2)*m*v^2
Where:
m = mass = 54 kg
v = velocity = 3 m/s
Since we are already given the needed values in the problem, direct substitution will be done:
KE = <span>(1/2)*m*v^2
</span>KE = <span>(1/2) * 54 * (3)^2
</span>KE = 243 J
