Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion
Putting all values in equation
s = 6950 m
So distance traveled during this acceleration will be 6950 m
Answer:
a) the magnitude of r is 184.62
b) the direction is 37.74° south of the negative x-axis
Explanation:
Given the data in the question;
as illustrated in the image blow;
To find the the magnitude of r, we will use the Pythagoras theorem
r² = y² + x²
r = √( y² + x²)
we substitute
r = √((-113)² + (-146)²)
r = √(12769 + 21316 )
r = √(34085 )
r = 184.62
Therefore, the magnitude of r is 184.62
To find its direction, we need to find ∅
from SOH CAH TOA
tan = opposite / adjacent
tan∅ = -113 / -146
tan∅ = 0.77397
∅ = tan⁻¹( 0.77397 )
∅ = 37.74°
Therefore, the direction is 37.74° south of the negative x-axis
