Answer:
a. 215.6 in^3
b. 1.51 lb
Step-by-step explanation:
The area of each hand grip hole is that of a circle of radius 0.6 in together with a rectangle 2 in long and 1.2 in wide. So, that area is ...
π·(0.6 in)^2 + (2 in)(1.2 in) = (0.36π +2.4) in^2
The area of the kickboard before the hand grip holes are put in is that of a semicircle of radius 5.5 in together with a rectangle 12 in long and 11 in wide. So, that area is ...
(1/2)·π·(5.5 in)^2 + (12 in)(11 in) = (15.125π +132) in^2
Taking the hand grip holes out, the top area of the board is ...
((15.125π +132) -2(0.36π +2.4)) in^2
= (14.405π + 127.2) in^2
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a. The volume is the product of the area and the thickness, so is ...
((14.405π +127.2) in^2)·(1.25 in) ≈ 215.568 in^3
__
b. The weight of the kickboard is the product of its volume and its density:
(215.568 in^3)(0.007 lb/in^3) ≈ 1.509 lb
Answer:
$3,675
Step-by-step explanation:
Simple Interest = principal x rate x time
so, simple interest = $35,000 x 3.5/100 x 3
Therefore, the answer is $3,675
Hooe this helped :)
7 + 3(4) - 2
7 + 12 - 2
19 - 2
= 17
Here's a table of the function y=-2x-3
Given:
In triangle DEF, HG is parallel to DF.
To find:
The value of x.
Solution:
In triangles DEF and GEH,
(Common angle)
(Corresponding angle)
(By AA property of similarity)
We know that corresponding sides of similar triangle are proportional.
Isolating variable terms, we get
Therefore, the value of x is equal to 4.
