Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
Answer:
16/27
Step-by-step explanation:
First let's convert this info an equation and then we will solve.
(2/3) * (8/9) = ?
( 2 * 8 ) / ( 3 * 9 ) = ?
( 16 ) / ( 27 ) = ?
16 / 27 = ?
So our fractional answer is 16/27.
In words this would be sixteen over twenty seven.
Cheers.
First, you need to distribute the right side of the equation : 8n - 2
Now the equation is : 20 - 7n = 8n - 2
Add 2 to both sides : 22 - 7n = 8n
Add 7n to both sides : 22 = 15n
Divide both sides by 15 : ( I had to round this one) 1.5 = n
H = 4(x + 3y) + 2
H = 4x + 12y + 2
H - 12y - 2 = 4x
(H - 12y - 2) / 4 = x or 1/4H - 3y - 1/2 = x
Just for you beautiful!
Use distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
(11,-4) is (x1,y1) and (-12,-4) is (x2,y2)
Plug in and simplify
d = sqrt((-12 - 11)^2 + (-4 - -4)^2)
d = sqrt((-23)^2 + (0)^2)
d = sqrt(529 + 0)
d = sqrt(529)
d = 23 (positive because length cannot be negative) ;)
