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kari74 [83]
2 years ago
8

Consider the function f(x) = (x + 2)2 + 1. Which of the following functions shifts the graph of f(x) to the right three units?

Mathematics
2 answers:
solong [7]2 years ago
8 0

Answer:

g(x) = (x – 1)2 + 1

Step-by-step explanation:

lakkis [162]2 years ago
5 0

Answer:

g(x) = (x – 1)2 + 1

Step-by-step explanation:

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Answer: 76

Step-by-step explanation:

well, we know that 15% of the X is 12, so we first use 6 15%, which is 90% 6X12=72. next, we would use 12/3, which is 4. 72+4=76.

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What is the absolute value of 7.4
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A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
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\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

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4(5a-2b)-2(4a-5b)<br><br><br> Expand the brackets and simplify the question
Nutka1998 [239]

Answer:

12a+2b

Step-by-step explanation:

1. Expand by distributing terms.

20a-8b-2(4a-5b)20a−8b−2(4a−5b)

2. Expand by distributing terms.

20a-8b-(8a-10b)20a−8b−(8a−10b)

 3. Remove parentheses.

20a-8b-8a+10b20a−8b−8a+10b

4.Collect like terms.

(20a-8a)+(-8b+10b)(20a−8a)+(−8b+10b)

5. Simplify.

12a+2b12a+2b

6.Answer

12a+2b

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