Question

PLEASEEEE HELPPP MEEE 6 and 7 PLEASE

Answer 1

Answer:

Question 6

$\left(5a+2\right)\left(a+4\right)=\:5a^2+22a+8$

Question 7

The width is 2x.

Step-by-step explanation:

                                           Question 6)

Expand

$(5a+2)(a+4)$

solving to the expand

$(5a+2)(a+4)$

• $\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$a=5a,\:b=2,\:c=a,\:d=4$

so the expression becomes

$=5aa+5a\cdot \:4+2a+2\cdot \:4$

$=5aa+5\cdot \:4a+2a+2\cdot \:4$

$=5a^2+20a+2a+8$

adding similar elements: 20a+2a=22a

$=5a^2+22a+8$

Hence,

$\left(5a+2\right)\left(a+4\right)=\:5a^2+22a+8$

                                                  Question 7)

Given

• $A\:=\:8x^2$

• $l=4x$

Using the formula

width = Area/Length

          $=\:\frac{8x^2}{4x}$

          $=2x$                  ∵ $\mathrm{Divide\:the\:numbers:}\:\frac{8}{4}=2$

Therefore, the width is 2x.