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3 years ago

Can you please help me

Mathematics

1 answer:

qwelly [4]3 years ago

8 0

Answer:

Fourth choice, 19/30

Step-by-step explanation:

Add 38 and 22 together, it's 60

Out of 60 times, he flipped heads 38 times, so it's 38/60

Simplify 38/60 with 2, 19/30

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Two vertices of a right triangle have the coordinates (−2, 5) and (9, 5) .

-Dominant- [34]

Length = √(y2-y1)² + (x2-x1)²
l = √(5 - 5)² + (9 + 2)²
l = √0² + 11²
l = √121
l = 11

In short, Your Answer would be 11 units

Hope this helps!

3 0

4 years ago

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If 1/x 1/x 1/x 1/x =24 what is x

kenny6666 [7]

Would you please elaborate on what you would like to know?

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3 years ago

A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is

timama [110]

Answer:

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Step-by-step explanation:

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3 years ago

Find bc if b(8,-7) and c(9-4,-2) midpoint

Pie

Answer:

Image result for find bc if b(8,-7) and c(9-4,-2) midpoint

To find the midpoint of any range, add the two numbers together and divide by 2. In this instance, 0 + 5 = 5, 5 / 2 = 2.5.

Step-by-step explanation:

5 0

3 years ago

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}$

3 0

4 years ago