Ask question

Ask question

All categories

3 years ago

7

At pizza hut, 9% of the pizzas made last night had extra cheese. if 27 pizzas has extra cheese, how many pizzas in all were made

last night

1 answer:

True [87]3 years ago

3 0

Answer: 300

You need to change 9% into a decimal so it would be 0.09

Then divide 27 ÷ 0.09 = 300

So 9% of 300 is 27

You might be interested in

Find the area of the rectilinear

riadik2000 [5.3K]

Answer:

52cm^2

Step-by-step explanation:

I did the splitting in my head and that's pretty hard to explain like this so, just BTW if your confused on where I got my lengths from.

(7*6) + (5*2)

(42) + (10)

52

I separated them into an almost square and a rectangle, then I found the area of each rectangle and then added them together.

Hopefully this was useful and you didn't have any issues with this!

5 0

3 years ago

in a survey of 2,000 who owned A certain type of car 1100 said they would buy that same type of car again what percent surveyed

ValentinkaMS [17]

55 percent is the answer

8 0

4 years ago

I need helppppp........

grin007 [14]

Answer:

B

Step-by-step explanation:

To do this, you need to complete the square.

$y=-2x^2-8x-13 \\\\y=-2(x^2+4x)-13 \\\\y=-2(x^2+4x+4)+8-13 \\\\y=-2(x+2)^2-5$

Therefore, the correct answer is choice B. Hope this helps!

7 0

4 years ago

Which of the following is equivalent to 3_-900 ?

pashok25 [27]

Do you still need help

4 0

3 years ago

Thirteen people on a softball team show up for a game. a)How many ways are there to choose 10 players to take the field? b)How m

marishachu [46]

Answer:

a) 286

b) 1,037,836,800

c) 285

Step-by-step explanation:

a) Since order is not important, the total possible number of ways to choose 10 players out of 13 is the following combination:

$C(13,10)=\frac{13!}{(13-10)!10! } \\C(13,10)=\frac{13*12*11*10!}{(3*2*1)10! }\\C(13,10) = 286$

b) The total number of possibilities to assign positions by the selecting 10 players is the permutation of 13 players for 10 positions:

$P(13,10) = \frac{13!}{(13-10)!}\\P(13,10) = 13*12*11*10*9*8*7*6*5*4\\P(13,10) =1,037,836,800$

c) The number of ways to pick 10 players including at least one woman is equal to the total number of ways to pick 10 players (found in item a) minus the the number of ways to pick 10 players without picking a single woman.

Since there 10 male players for 10 positions, there is only one possible way to pick a team without women, therefore:

$P=286-1 =285$

6 0

3 years ago