Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
Erm
x+y=6
xy=12
x+y=6
y=6-x
sub back
xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i
x=3+/-i√3
the numbers are 3+i√3 and 3-i√3
no real numbers tho
Answer:
3
Step-by-step explanation:
A direct variation is of the form
y = kx
We know x and y so we can find k
81 = k *27
Divide each side by 27
81/27 = 27k/27
3=k
The constant of variation is 3
Answer:
Part 1. 0.9259 % per year
Part 2. P = 281.4e^(0.009 259t); 338.6 million
Step-by-step explanation:
Data:
P₀ = 281.4 million
P = 308.7 million
Part 1. Growth rate
t = 2010 - 2000 = 10 yr
P = P₀e^(rt)
308.7 = 281.4e^(10r)
e^(10r) = 1.0970
10r = ln1.0970
r = (ln1.0970)/10 = (0.092 59)/10 = 0.009 259
r = 0.9259 % per year
The 10-year continuous growth rate is 0.9259 % per year.
Part 2. Population model
The population model is
P = 281.4e^(0.009 259t)
where P is in millions and t is the number of years since 2000.
By 2020,
P = 281.4e^(0.009 259 × 20) = 281.4e^0.1852 = 281.4 × 1.203
P = 338.6 million
The estimated population in 2020 is 338.6 million.
Answer:
10
Step-by-step explanation:
