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3 years ago

7

What is 28x34+3767.

2 answers:

Anna [14]3 years ago

7 0

The answer is 4719

Please mark brainlyest...

Mademuasel [1]3 years ago

4 0

Answer:

4719

Step-by-step explanation:

You might be interested in

What is 2/4 + 4/5 - 7/10 ? Please help

Radda [10]

Make sure they have all common denominators
$\frac{2}{4} + \frac{4}{5} - \frac{7}{10}$

$\frac{2}{4} * \frac{5}{5} = \frac{10}{20}$

$\frac{4}{5} * \frac{4}{4} = \frac{16}{20}$

$\frac{7}{10} * \frac{2}{2} = \frac{14}{20}$

$\frac{10}{20} + \frac{16}{20} - \frac{14}{20}$

Add $\frac{10}{20} + \frac{16}{20} = \frac{26}{20}$
$\frac{26}{20} - \frac{14}{20} = \frac{12}{20}$

To simplify, you must find the largest common factor which 4
In $\frac{12}{20}$
12÷4=3 and 20÷4=5

The answer is $\frac{3}{5}$

7 0

3 years ago

2(3+9x) answer this for me plz lol

Gre4nikov [31]

Answer:

6+18x

Step-by-step explanation:

You typically would use PEMDAS in this situation but in the parenthesis, you can't add the 3 and the 9x together, so you just skip to 2*3 and 2*9x

4 0

2 years ago

Read 2 more answers

Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.

lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is <u>tested if the mean lifetime is not greater than 220,000 miles</u>, that is:

$H_0: \mu \leq 220000$

At the alternative hypothesis, it is <u>tested if the mean lifetime is greater than 220,000 miles</u>, that is:

$H_1: \mu > 220000$ .

We have the <u>standard deviation for the sample</u>, thus, the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem:

$\overline{x} = 226450, \mu = 220000, s = 11500, n = 23$

Then, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}$

$t = 2.69$

We have a right-tailed test(test if the mean is greater than a value), with <u>t = 2.69</u> and 23 - 1 = <u>22 df.</u>

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0

2 years ago

suppose a city with population 200,000 has been growing at a rate of 3% per year if this rate continues find the population of t

Gennadij [26K]

Answer:

345.000

Step-by-step explanation:

8 0

2 years ago

What is the following quotient?

Sergio039 [100]

Answer:

$\frac{\sqrt{3} }{4}$

Step-by-step explanation:

$\frac{1}{1+\sqrt{3} }$

basically we want to get rid of the √3 on the denominator

to do so we multiply it by itself so it is a perfect square

but whatever we do to the top we must do to the bottom so we multiply the numerator and denominator by √3

$\frac{1*\sqrt{3} }{1+\sqrt{3}*\sqrt{3} }=\frac{\sqrt{3} }{1+\sqrt{9} } =\frac{\sqrt{3} }{1+3} =\frac{\sqrt{3} }{4}$

notes : √3 × √3 = √9 which is a perfect square that simplfies to 3

3 0

1 year ago