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3 years ago

What is 6/7 of2/3? pls help \

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

Answer:

4/7

Step-by-step explanation:

givi [52]3 years ago

4 0

6/7 ÷ 2/3 = 6/7 * 3/2 = 18/14 --->1 4/14 ---> 1 2/7

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Express 64^3/2 in simplest radical form

tatiyna

Answer:

16 im sure :)

Step-by-step explanation:

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3 years ago

A rectangular prism has a length of 12in, a height of 5in, and a width of 8in. What is its volume, in cubic in?

Dovator [93]

Answer: 480 in^3

Step-by-step explanation:

v= l * w*h

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3 years ago

Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func

mote1985 [20]

Solution:

The given Polynomial is :

$f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$

By Rational Root theorem the of Zeroes of the Polynopmial are:

$\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4$

But , $f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0$

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial $f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$ .

8 0

3 years ago

Read 2 more answers

A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of

ddd [48]

There are

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ways of pairing up any 2 members from the pool of $2n$ contestants. Note that

$(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)$

so that

$\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}$

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2 years ago

What is 7 divided by 50

Anastaziya [24]

Answer:

0.14

Hope this helps :-)

8 0

3 years ago