For the given equation,4x²−y²−24x−4y+28=0.The center is (h,k)=(3,−2), vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2), foci is (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)
<h3>What is the equation?</h3>
An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the equation of the hyperbola is,
4x²−y²−24x−4y+28=0
Comparing the equation with the standard equation we get,
Center (h,k)=(3,−2)
Vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2)
Foci (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)
Asymptotes y=2x−8 and y=−2x+4
Thus, for the given equation,4x²−y²−24x−4y+28=0.The center is (h,k)=(3,−2), vertex (h+a,k)=(4,−2) and (h−a,k)=(2,−2), foci is (h+c,k)=(5.23,−2) and (h−c,k)=(0.77,−2)
Learn more about the equation here,
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