Y2-y1=m(x2-x1)
Y- (-3)=1/3(x-3)
D
Divide the whole thing by 2
2(X^2+8x-5)
X^2+8x. =5
Half of 8 is 4 sq it so you add 16
X^2+8x+16= 5+16
(X+4)^2=21
When X = -9 Y = 1 you can find this by going to -9 on the x axis and finding where the line is there
Answer:
Probability distribution
X P(X)
0 1/8
1 3/8
2 3/8
3 1/8
Step-by-step explanation:
When a coin is tossed there are two outcomes head and tail. When three coins are tossed the possible outcomes are
Sample space=S={HTH,THH,TTH,HHH,HTT,THT,TTT,HHT}
The total number of outcomes is n(S)=8. The X be the random variable counting number of tails in each outcome and so X can take values as 0,1,2,3. The probabilities can be computed as P(X)=n(X)/n(S). The probabilities are calculated as under:
X Outcomes P(X)
0 HHH 1/8
1 HHT,THH,HTH 3/8
2 TTH,HTT,THT 3/8
3 TTT 1/8
The probability distribution of X is as under:
X P(X)
0 1/8
1 3/8
2 3/8
3 1/8
