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tankabanditka [31]
3 years ago
14

Write 500as a product of a prime number factors each factors must be greater than 1 and can have on 1 and its self as factors

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0
500 = 2 * 2 * 5 * 5 * 5
 

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2 years ago
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Question 17, 19 and 21 ?
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3 years ago
To steam rice, Paul uses m cups of water for every p
GenaCL600 [577]

Answer:

\frac{(p + 2)m}{p}

Step-by-step explanation:

Given

m cups of water = p cups of rice

Required

Cups of water required for p + 2 cups of rice

<em>The question shows a direct proportion between cups of rice and cups of water.</em>

<em>So, the first step is to get the proportionality constant (k)</em>

<em />

This is calculated using the following expression;

m = k * p

Where k represents cups of water and p represents cups of rice

Make k the subject of formula

k = \frac{m}{p}

Let x represents cups of water when cups of rice becomes p + 2;

k becomes:

k = \frac{x}{p + 2}

Equate both expressions of k; to give

\frac{m}{p} = \frac{x}{p + 2}

Multiply both sides by p + 2

(p + 2) * \frac{m}{p} =(p + 2) *  \frac{x}{p + 2}

(p + 2) * \frac{m}{p} =x

x = (p + 2) * \frac{m}{p}

x =  \frac{(p + 2)m}{p}

<em>Hence, the expression that represents the cups of water needed is </em>\frac{(p + 2)m}{p}<em></em>

4 0
3 years ago
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.0 ounces and a standard deviation of 1.1 ounces.

This means that \mu = 8, \sigma = 1.1

(a) If 5 potatoes are randomly selected, find the probability that the mean weight is less than 9.3 ounces?

n = 5 means that s = \frac{1.1}{\sqrt{5}} = 0.4919

This probability is the pvalue of Z when X = 9.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{9.3 - 8}{0.4919}

Z = 2.64

Z = 2.64 has a pvalue of 0.9959

0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.0 ounces?

n = 6 means that s = \frac{1.1}{\sqrt{6}} = 0.4491

This probability is 1 subtracted by the pvalue of Z when X = 9. So

Z = \frac{X - \mu}{s}

Z = \frac{9 - 8}{0.4491}

Z = 2.23

Z = 2.23 has a pvalue of 0.9871

1 - 0.9871 = 0.0129

0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

8 0
3 years ago
What is the percent of discount on a $37.50<br> dress on sale for $26.25?
tankabanditka [31]

Answer:

30% discount.

Step-by-step explanation:

4 0
3 years ago
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