Write 500as a product of a prime number factors each factors must be greater than 1 and can have on 1 and its self as factors

can someone help me with this i have autism and my parents aren't home I need some help with this pls will give brainly

svetoff [14.1K]

I can barely see the majority of the questions
i cant do all but to multiply fractions, you just multiply the numerator and the denominator together
so 3 2/3 x 6
change 3 2/3 to an improper fraction
9/3 x 6/1 = 27/3 which is 9/1 reduced
10 x 1 2/3 is 10/1 x 5/3 = 50/3

3 0

2 years ago

Read 2 more answers

Question 17, 19 and 21 ?

Vaselesa [24]

If this is Textbook work- use SLADER (the app or the website)

3 0

3 years ago

To steam rice, Paul uses m cups of water for every p

GenaCL600 [577]

Answer:

$\frac{(p + 2)m}{p}$

Step-by-step explanation:

Given

m cups of water = p cups of rice

Required

Cups of water required for p + 2 cups of rice

The question shows a direct proportion between cups of rice and cups of water.

So, the first step is to get the proportionality constant (k)

This is calculated using the following expression;

$m = k * p$

Where k represents cups of water and p represents cups of rice

Make k the subject of formula

$k = \frac{m}{p}$

Let x represents cups of water when cups of rice becomes p + 2;

k becomes:

$k = \frac{x}{p + 2}$

Equate both expressions of k; to give

$\frac{m}{p} = \frac{x}{p + 2}$

Multiply both sides by p + 2

$(p + 2) * \frac{m}{p} =(p + 2) * \frac{x}{p + 2}$

$(p + 2) * \frac{m}{p} =x$

$x = (p + 2) * \frac{m}{p}$

$x = \frac{(p + 2)m}{p}$

Hence, the expression that represents the cups of water needed is $\frac{(p + 2)m}{p}$

4 0

3 years ago

Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

svet-max [94.6K]

Answer:

a) 0.9959 = 99.59% probability that the mean weight is less than 9.3 ounces

b) 0.0129 = 1.29% probability that the mean weight is more than 9.0 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .