F -- so multiply first terms in each set....(x)(2x) O -- multiply outside terms in each set...(3)(x) I -- multiply inside terms in each set....(-4)(2x) L -- multiply last terms in each set.......(-4)(3)
so we have : (x)(2x) + (3)(x) + (-4)(2x) + (-4)(3).....answer C
Get them to have a common denominator so you can add them (1/3)×2= 2/6 and (1/2)×3= 3/6 Add them together (2/6)+ (3/6)= 5/6 So 5/6 of the class planted either marigolds or tulips and 1/6 of the class planted neither
