Answer:
The mass of present is
Explanation:
From the question we are told that
The diameter of the spot is
The volume of the solution present is
The mass of ions in one liter of solution is
Generally the mass of ions present is v is mathematically represented as
Converting to nanograms
We have
<u>Answer:</u> The standard potential of the cell is 0.77 V
<u>Explanation:</u>
We know that:
The substance having highest positive reduction potential will always get reduced and will undergo reduction reaction.
The half reaction follows:
<u>Oxidation half reaction:</u>
<u>Reduction half reaction:</u> ( × 2)
To calculate the of the reaction, we use the equation:
Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Putting values in above equation follows:
Hence, the standard potential of the cell is 0.77 V
Answer:
V₂ = 145.35 L
Explanation:
Given data:
Initial volume = 400 L
Initial pressure = 300 mmHg (300/760 =0.39 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂ /T₁ P₂
V₂ = 0.39 atm × 400 L × 273 K / 293 K × 1 atm
V₂ = 42588 atm.L.K /293 K.atm
V₂ = 145.35 L
Answer:
A-Shape
C-state
Explanation:
reactivity and flammability are both indicators of chemicals changes