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Harlamova29_29 [7]
3 years ago
8

How is the density of an object in kg/L related to its density in g/mL? (1 point)​

Chemistry
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

kg =1000g ml =1/1000 L

Explanation:

1000g/L=1g/1/1000L=1000g/L

The same

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97 mols I think approximately
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Taylor, a MIC 206 student needs to determine the OCD of a sample of Escherichia coli. She performed dilutions using four 9 ml di
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Answer:

1.37 x 10^6 CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of 10^{-4}.

Next is to divide the colony forming unit from the dilution by the dilution factor:

   137/10^{-4} = 137 x 10^4

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

   137 x 10^4/1 = 1.37 x 10^6

Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x 10^6.

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4 years ago
Which of the following contains only one
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Answer:

A. elements

<em>I</em><em> hope</em><em> it's</em><em> helps</em><em> you</em>

7 0
3 years ago
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What tool would you use to measure volume
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Answer:

beakers and flasks

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An aqueous solution of 1.29 M ethanol, CH3CH2OH, has a density of 0.988 g/mL. The percent by mass of CH3CH2OH in the solution is
anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g

Now, the mass of the ethanol:

m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g

Finally, the by mass percent is:

m/m=\frac{59.34g}{988g}*100\\%

%m=6%

Best regards.

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3 years ago
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