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anastassius [24]
3 years ago
6

Which of the following choices results in a decrease in the overall density of a product? Question 5 options: Increase the volum

e of the product (and keep the same materiel) Decrease the volume of the product (and keep the same materiel) Increase the weight of the product (and keep the same materiel) Decrease the weight of the product (and keep the same materiel)
Chemistry
2 answers:
Elza [17]3 years ago
8 0

Answer:

When the volume of product increases.

When the weight of the product decreases.

Option (a) and (d) are correct.

Explanation:

The overall density of the product can be decreased:

a. Increase the volume of the product (and keep the material same)

d. Decrease the weight of the product ( and keep the same material ).

Density is calculated as the ratio of mass to the volume.  

Density is inversely related to volume and directly related to mass.

So, when the mass of the product is increased then the density will increase keeping the material same. Density will also increase when the volume of the product decreased.

dedylja [7]3 years ago
7 0

Answer:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Explanation:

Hello,

Based on the equation defining the density:

\rho =\frac{m}{V}

Whereas m is the mass and V the volume, in order to decrease the density it is necessary to:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Due to the fact that the volume is inversely proportional to the density and the weight is directly proportional to the density.

Best regards.

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27,397.23 L would be needed for a successful trip.

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The problem gives us <u>the density (ρ) of the fuel,</u> by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=\frac{mass}{Volume}=\frac{803g}{1L}  =803\frac{g}{L}

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We calculate the required volume (V), using the mass and density:

803 g/L = \frac{2.2*10^{7}g }{V} \\V=\frac{2.2*10^{7}g }{803g/L}\\ V=27397.26 L

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A compound has a percent composition of 54.5% carbon, 9.3% hydrogen and 36.2 % oxygen.If its molar mass is 88 g/mol, what is its
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Answer:

C₄H₈O₂.

Explanation:

  • Firstly, we can calculate the no. of moles (n) of each component using the relation:

<em>n = mass/atomic mass,</em>

mol C = mass/(atomic mass) = (54.5 g)/(12.0 g/mol) = 4.54 mol.

mol H = mass/(atomic mass) = (9.3 g)/(1.0 g/mol) = 9.3 mol.

mol O = mass/(atomic mass) = (36.2 g)/(16.0 g/mol) = 2.26 mol.

  • To get the empirical formula, we divide by the lowest no. of moles (2.26 mol) of O:

∴ C: H: O = (4.54 mol/2.26 mol) : (9.3 mol/2.26 mol) : (2.26 mol/2.26 mol) = 2: 4: 1.

<em>∴ Empirical formula mass of (C₂H₄O) = 2(atomic mass of C) + 4(atomic mass of H) + 1(atomic mass of O) =</em> 2(12.0 g/mol) + 4(1.0 g/mol) + (16.0 g/mol)<em> = 44.0 g/mol.</em>

∴ Number of times empirical mass goes into molecular mass = (88.0 g/mol)/(44.0 g/mol) = 2.0 times.

∴ The molecular formula is, 2(C₂H₄O), that is; <em>(C₄H₈O₂)</em>

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