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anastassius [24]
3 years ago
6

Which of the following choices results in a decrease in the overall density of a product? Question 5 options: Increase the volum

e of the product (and keep the same materiel) Decrease the volume of the product (and keep the same materiel) Increase the weight of the product (and keep the same materiel) Decrease the weight of the product (and keep the same materiel)
Chemistry
2 answers:
Elza [17]3 years ago
8 0

Answer:

When the volume of product increases.

When the weight of the product decreases.

Option (a) and (d) are correct.

Explanation:

The overall density of the product can be decreased:

a. Increase the volume of the product (and keep the material same)

d. Decrease the weight of the product ( and keep the same material ).

Density is calculated as the ratio of mass to the volume.  

Density is inversely related to volume and directly related to mass.

So, when the mass of the product is increased then the density will increase keeping the material same. Density will also increase when the volume of the product decreased.

dedylja [7]3 years ago
7 0

Answer:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Explanation:

Hello,

Based on the equation defining the density:

\rho =\frac{m}{V}

Whereas m is the mass and V the volume, in order to decrease the density it is necessary to:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Due to the fact that the volume is inversely proportional to the density and the weight is directly proportional to the density.

Best regards.

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Iron (III) oxide reacts with solid carbon in the followed reaction: 2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g) What mass of Fe2O3 is n
Veseljchak [2.6K]

953.6 g of iron (III) oxide (Fe₂O₃)

Explanation:

We have the following chemical reaction:

2 Fe₂O₃ (s) + 3 C (s) → 4 Fe (s) + 3 CO₂ (g)

We calculate the number of moles of CO₂ by using the following formula:

pressure × volume = number of moles × gas constant × temperature

number of moles = (pressure × volume) / (gas constant × temperature)

number of moles of CO₂ = (2.1 × 100) / (0.082 × 300)

number of moles of CO₂ = 8.54 moles

Taking in account the chemical reaction we devise the following reasoning:

if         2 mole of Fe₂O₃ produces 3 mole of CO₂

then   X moles of Fe₂O₃ produces 8.54 mole of CO₂

X = (2 × 8.54) / 3 = 5.69 moles of Fe₂O₃

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of Fe₂O₃ = 5.69 × 160 = 953.6 g

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