Which of the following choices results in a decrease in the overall density of a product? Question 5 options: Increase the volum
2 answers:
Answer:
- Increase the volume of the product (and keep the same materiel).
- Increase the weight of the product (and keep the same materiel).
Explanation:
Hello,
Based on the equation defining the density:
Whereas is the mass and
the volume, in order to decrease the density it is necessary to:
- Increase the volume of the product (and keep the same materiel).
- Increase the weight of the product (and keep the same materiel).
Due to the fact that the volume is inversely proportional to the density and the weight is directly proportional to the density.
Best regards.
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Answer:
The attractive force is negative and MgO has a higher melting point
Explanation:
From Couloumb's law:
Energy of interaction, E = k
where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.
If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).
In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten
The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.
Hence the compound MgO would have a higher melting point than NaF.