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anastassius [24]
4 years ago
6

Which of the following choices results in a decrease in the overall density of a product? Question 5 options: Increase the volum

e of the product (and keep the same materiel) Decrease the volume of the product (and keep the same materiel) Increase the weight of the product (and keep the same materiel) Decrease the weight of the product (and keep the same materiel)
Chemistry
2 answers:
Elza [17]4 years ago
8 0

Answer:

When the volume of product increases.

When the weight of the product decreases.

Option (a) and (d) are correct.

Explanation:

The overall density of the product can be decreased:

a. Increase the volume of the product (and keep the material same)

d. Decrease the weight of the product ( and keep the same material ).

Density is calculated as the ratio of mass to the volume.  

Density is inversely related to volume and directly related to mass.

So, when the mass of the product is increased then the density will increase keeping the material same. Density will also increase when the volume of the product decreased.

dedylja [7]4 years ago
7 0

Answer:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Explanation:

Hello,

Based on the equation defining the density:

\rho =\frac{m}{V}

Whereas m is the mass and V the volume, in order to decrease the density it is necessary to:

- Increase the volume of the product (and keep the same materiel).

- Increase the weight of the product (and keep the same materiel).

Due to the fact that the volume is inversely proportional to the density and the weight is directly proportional to the density.

Best regards.

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3 years ago
3. SE7.12D The cell organelle responsible for providing energy for cell processes in plant
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What is the enthalpy for reaction 1 reversed? reaction 1 reversed: 2co2 + 3h2o→c2h5oh + 3o2 express your answer numerically in k
Rama09 [41]

Answer: The enthalpy of the given reaction is 1234.8kJ/mol.

Explanation: Enthalpy change of the reaction is the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

For the given reaction:

2CO_2(g)+3H_2O(g)\rightarrow C_2H_5OH(l)+3O_2(g)

H_f_{(CO_2)}=-393.5kJ/mol

H_f_{(H_2O)}=-241.8kJ/mol

H_f_{(C_2H_5OH)}=-277.6kJ/mol

H_f_{(O_2)}=0kJ/mol

\Delta H_{rxn}=\Delta H_f_{(C_2H_5OH)}+3\Delta H_f_{(O_2)}-[2\Delta H_f_{(CO_2)}+3\Delta H_f_{(H_2O)}]

Putting values in above equation, we get:

\Delta H_{rxn}=[-277.6+3(0)]-[2(-393.5)+3(-241.8)]kJ/mol

\Delta H_{rxn}=1234.8kJ/mol

7 0
3 years ago
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